b^2=-4b+5

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Solution for b^2=-4b+5 equation:


Simplifying
b2 = -4b + 5

Reorder the terms:
b2 = 5 + -4b

Solving
b2 = 5 + -4b

Solving for variable 'b'.

Reorder the terms:
-5 + 4b + b2 = 5 + -4b + -5 + 4b

Reorder the terms:
-5 + 4b + b2 = 5 + -5 + -4b + 4b

Combine like terms: 5 + -5 = 0
-5 + 4b + b2 = 0 + -4b + 4b
-5 + 4b + b2 = -4b + 4b

Combine like terms: -4b + 4b = 0
-5 + 4b + b2 = 0

Factor a trinomial.
(-5 + -1b)(1 + -1b) = 0

Subproblem 1

Set the factor '(-5 + -1b)' equal to zero and attempt to solve: Simplifying -5 + -1b = 0 Solving -5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1b = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1b = 0 + 5 -1b = 0 + 5 Combine like terms: 0 + 5 = 5 -1b = 5 Divide each side by '-1'. b = -5 Simplifying b = -5

Subproblem 2

Set the factor '(1 + -1b)' equal to zero and attempt to solve: Simplifying 1 + -1b = 0 Solving 1 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1b = 0 + -1 -1b = 0 + -1 Combine like terms: 0 + -1 = -1 -1b = -1 Divide each side by '-1'. b = 1 Simplifying b = 1

Solution

b = {-5, 1}

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